Can you please show me how you solved the equation (x/6 + x/12 + x/7 + 5 + x/2 + 4 = x)
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Hi Cosma,
Here is one way (not saying it's the only one :)
First step: get all multiples of 2 to the same high denominator:
x/6 + x/12 + x/7 + 5 + x/2 + 4 = x <=> 2x/12 + x/12 + x/7 + 5 + 6x/12 + 4 = x
Then you add them up:
2x/12 + x/12 + x/7 + 5 + 6x/12 + 4 = x <=> 9x/12 + x/7 + 9 = x
And actually your equation is equivalent to 3x/4 + x/7 + 9 = x
Then you bring it all to the same denominator which gives you 21x/28 + 4x/28 + 9 = x
And finally you have 9 = 3x/28 which is equivalent to x = 28*3 = 84
Hope this helps :)
I would find the common denominator for ALL numbers together:
- 12= 2 x 2 x 3
- 6 > included in the 12
- 2 > included in the 12
- 7 = prime
Common denominator: 12 x 7
If you are more or less good with math you should have no issue, since it´s multiplications of one single digit.
Hope it helps!
Cheers,
Clara
Agree with Hugo. That's how I would do it too. :)