following the same assumption of finding the bus riders per route, shouldn't the cost of insurance be:
50 $ / day * 1 day/ 10 hrs * 1 hrs/20 miles =0.25 $/route
instead of the current cost of fuel of:
50/10 translating to 50 $ / day * 1 day/ 10 hrs = 5$/day
making the finale cost be 100.25 $/ route ---> 67 passengers as the finale answer for breakeven
hey Rawan:)
based on the info you provided so far:
I would say that your intuition is good, but the issue is mixing up units and what the cost actually depends on. insurance is typically time-based, not distance-based. so once you already convert 50$/day into 5$/hour, you should stop there if the route takes 1 hour. multiplying again by miles (1 hr / 20 miles) double-counts and artificially shrinks the cost.
so the clean logic is: insurance per route = 50$/day ÷ 10 hours = 5$ per route (assuming 1-hour route). no need to adjust for miles unless the case explicitly says insurance depends on distance, which is unusual.
your corrected total cost per route should therefore stay at 100 + 5 = 105$, not 100.25$. that will slightly increase the breakeven passengers compared to your 67.
hope this helps!
best,
Alessa :)
Hey Anonymous,
Always happy to help, but we need more context. I don’t see the insurance/bus section in the “related case” at your question’s link.
Do you mind sharing more?
Best,
Tom
Hi Rawan,
We need to know the prompt + proposed solution to be able to help :)
