Hey Hans :)
If we assume 600,000 total visits and that each pass holder uses their pass 10 times per season, then the number of unique pass holders is 600,000 ÷ 10 = 60,000. So yes, your calculation is correct under that assumption.
best,
Alessa :)
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i think it would more make sense if the users of the pass is visit 20 times, since it would cheaper per visit for them. if we do this, we still able use the respective current number
For the calculation of annual pass holders, isn't it 60,000 passes, given that we assume that 600,000 visitors use their pass 10 times per season?
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Hi Hans,
If we assume:
- 600,000 total visits per season
- Each annual pass holder visits 10 times on average
Then the number of unique pass holders is simply:
600,000 ÷ 10 = 60,000 pass holders.
So yes, it would be 60,000 annual pass holders under that assumption.
The only caveat: this holds true if all 600,000 visits are by pass holders and each uses the pass exactly 10 times. If some visits are from single-ticket buyers, or if pass usage varies a lot (some 3 times, some 20), the actual number would be different.
Best,
Evelina
Yes, the suggested answer wrongfully stated 30,000 passes.
